A ball is thrown vertically upwards from top of a tower with a velocity u . This ball rea

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2.Motion in Straight Line

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A ball is thrown vertically upwards from the top of a tower with a velocity $u$. This ball reaches the ground level with a velocity $4\,u$. The height of the tower is

A

$\frac{3u^2}{g}$

B

$\frac{4u^2}{g}$

C

$\frac{6u^2}{g}$

D

$\frac{15u^2}{2g}$

Solution

$(4 u)^{2}=u^{2}+2 g \cdot h$

$\mathrm{h}=\frac{15 \mathrm{u}^{2}}{2 \mathrm{g}}$

Standard 11

Physics

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